A fixed rooted skeleton carries an independent Brownian motion on every edge, so each leaf sees a Brownian path and two leaves share their history up to their most recent common ancestor: Σij = t(i ∧ j). Ruin asks that all leaves cross their own barriers u qj at one common time. Two things decide the answer. The exponent comes from the quadratic programme min{ w⊤Σ−1w : w ≥ q }, which is an obstacle problem on an electrical network: each edge has resistance equal to its length, and the multipliers are the currents injected at the leaves — an active leaf pays, a strictly slack leaf is carried above its barrier by the others. A binding leaf with zero multiplier still contributes a Gaussian boundary factor. The ruin constant combines the reversed trunk with what happens in the last window of length κ/u², where each leaf sprouts a whole genealogy whose descendants must all be above the barrier at that same instant. From E. Hashorva, Simultaneous ruin on Brownian metric trees with terminal groups.